SOLUTION: joye built a rectangular gared whose lenghts was eight feet more than triple it's width. if the perimeter was two hundred sixteen feet, what is the length of the garden

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Question 499916: joye built a rectangular gared whose lenghts was eight feet more than triple it's width. if the perimeter was two hundred sixteen feet, what is the length of the garden
Answer by oberobic(2304) About Me  (Show Source):
You can put this solution on YOUR website!
P = perimeter
L = length
W = width
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P = 2L + 2W = 2(L+W)
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P = 216 ft. (given)
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The length is 8 ft more than 3 times the width.
L = 3*W + 8
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2(L+W) = 216
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Divide both sides by 2
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L+W = 108
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Substitute for L
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3*W+8 + W = 108
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4W + 8 = 108
4W = 100
W = 25
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The width is 25 ft.
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Substitute to find L.
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L+W = 108
L + 25 = 108
L = 83
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The length is 83 ft.
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Always check your work!
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In this case, use the other statement and equation.
The length is 8 ft more than 3 times the width.
L = 3W + 8
L = 83
3W + 8 = 3(25) + 8
3*25 + 8 = 83
Correct!
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Re-read the question to make sure you answer it.
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What is the length of the garden?
The garden is 83 ft. in length.
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Done.