# SOLUTION: During the first part of a trip a canoeist travels 59 miles at a certain speed. The canoeist travels 25 miles on the second part of the trip at a speed of 5mph slower. The total ti

Algebra ->  Algebra  -> Length-and-distance -> SOLUTION: During the first part of a trip a canoeist travels 59 miles at a certain speed. The canoeist travels 25 miles on the second part of the trip at a speed of 5mph slower. The total ti      Log On

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 Question 466400: During the first part of a trip a canoeist travels 59 miles at a certain speed. The canoeist travels 25 miles on the second part of the trip at a speed of 5mph slower. The total time for the trip was 5 hour. What was the speed on each part of the trip?Answer by mananth(12270)   (Show Source): You can put this solution on YOUR website!first part 59 miles second part 25 miles speed in first part x mph speed second part x -5 mph Total rowing time 5 hours Time first part 59 / x Time second part 25 / ( x -5 ) Time first part + time second part = 5 hours 59/x+25 /(x-5)= 5 LCD = x*(x-5) multiply the equation by the LCD we get 59*(x-5)+25x= 5 59x-295 +25x=5x^2-25x 84x-295=5X^2 5x^2-84x+295= 0 5x^2-84x+295=0 / 5 x^2-16.8x+59=0 Find the roots of the equation by quadratic formula a= 1 b= 10 c= -9191 b^2-4ac= 100 - 36764 b^2-4ac= 36864 =192 x1=(-10 +192)/ 2 x1= 91 x2=( -10 -192 ) / 2 x2= -101 Ignore negative value x=91mph First part 86 mph second part m.ananth@hotmail.ca