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Question 442382: Find coordinates for the point equidistant from (2,1) (2,-4) (-3,1)
Please i really need your help ! thankyou
Found 3 solutions by MathLover1, Edwin McCravy, josmiceli: Answer by MathLover1(20849) (Show Source):
You can put this solution on YOUR website!
Find coordinates for the point equidistant from (2,1) (2,-4) (-3,1)
Let P(x, y) be the point.
The distance between (x, y) and (2, 1) is:
The distance between (x, y) and (2, -4) is:
The distance between (x, y) and (-3, 1) is:
So we have the following system of equations in terms of x, y, and D:



Square through the square roots:


Since these all equal D^2, we have two equations set equal to each other and we will produce a system of two equations that we are all used to.
Setting equation 1 = equation 2:
...now find
Setting equation 1 = equation 3:
so, the point is (-1/2, -2/5)
Answer by Edwin McCravy(20054) (Show Source): Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Call the point equidistant from the 3 given points (x,y)
The distance, , from (2,1)
(1) 
The distance, , from (2,-4)
(2) 
The distance, , from (-3,1)
(3) 
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From (1) to (2)


Subtract from both sides





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From (2) to (3)









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The coordinates of the point are (-1/2,-3/2)
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check answer:
(1) 
(1) 
(1) 
(1) 
(1) 
(1) 
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(2) 
(2) 
(2) 
(2) 
(2) 
(2) 
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(3) 
(3) 
(3) 
(3) 
(3) 
(3)
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