SOLUTION: What is the equation of the line perpendicular to the line joining (4, 2) and (3, -5) and passing through (4, 2)?

Question 323902: What is the equation of the line perpendicular to the line joining (4, 2) and (3, -5) and passing through (4, 2)?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
(4,2 ) (3, -5)
slope of the line joining them is
m= y2-y1/x2-x1
m=-5-2 / 3-4
=-7/-1
m=7
so the general equation is y=7x+b
plug the value of any one poin to get the value of b
2=28+b
b=-26

The line perpendicular to it will have slope o -1/7
The equation for that lineis y= -1/7 x -26

RELATED QUESTIONS
What is the equation of the line passing through the point (6,-3) and perpendicular to... (answered by tutorcecilia)

What is the standard form of the equation of the line passing through the point (-4,-1)... (answered by sachi)

Find the equation of the line passing through (1/2, 3/4) and is perpendicular to... (answered by AnlytcPhil)

The line passing through (-4, 2) and (2, -3) is perpendicular to the line passing through (answered by josgarithmetic,MathTherapy)

choose the equation for the line passing through (4 -2) and perpendicular to... (answered by tools)

The line passing through (-2,y) and (1,0) is perpendicular to line joining (3,3) and... (answered by subudear,richwmiller)

Write an equation of the line passing through (4,-2) and perpendicular to x= 5/4 y -... (answered by 2897696)

Write an equation of the line passing through (4,-2) and perpendicular to x= 5/4 y - 2 (answered by LinnW)

1. Find the equation of the line joining the points ( 5, 1) and (-7, -7) ( 5 marks) (answered by Alan3354)