SOLUTION: Throwing a wrench. An angry construction worker throws
his wrench downward from a height of 128 feet with an
initial velocity of 32 feet per second. The height of the
wrench abo
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-> SOLUTION: Throwing a wrench. An angry construction worker throws
his wrench downward from a height of 128 feet with an
initial velocity of 32 feet per second. The height of the
wrench abo
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Question 275603: Throwing a wrench. An angry construction worker throws
his wrench downward from a height of 128 feet with an
initial velocity of 32 feet per second. The height of the
wrench above the ground after t seconds is given
by S(t)= -16t^2 32t + 128.
a) What is the height of the wrench after 1 second?
b) How long does it take for the wrench to reach the
ground? Answer by solver91311(24713) (Show Source):
Where is the acceleration in feet per second due to gravity, namely
and is the initial velocity, here
and is the initial height, here 128 feet.
Hence:
The height of the wrench after 1 second is the value of the function when . Plug in the value and do the arithmetic:
The height of the ground is zero, so the time value when is the length of time it takes for the wrench to hit the ground -- presuming that the wrench didn't hit something else, perhaps the worker's boss' head -- before it hit the ground. So, solve the quadratic:
