SOLUTION: The equation of the line that goes through the point ( 6 ,2 ) and is parallel to the line 2 x + 5 y = 4 can be written in the form y = mx+b where m is:_ and where b is:

SOLUTION: The equation of the line that goes through the point ( 6 ,2 ) and is parallel to the line 2 x + 5 y = 4 can be written in the form y = mx+b where m is:_ and where b is:_

Question 274923: The equation of the line that goes through the point ( 6 ,2 ) and is parallel to the line 2 x + 5 y = 4 can be written in the form y = mx+b where m is:_
and where b is:_
Found 2 solutions by JBarnum, jim_thompson5910:
Answer by JBarnum(2146) (Show Source): You can put this solution on YOUR website!
just put the equation in the y-intercept form u have shown

to find b you will need to put the point in the eqaution and solve for b

Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
First solve for y to get

Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line

Since any two parallel lines have the same slope we know the slope of the unknown line is (its from the slope of which is also ). Also since the unknown line goes through (6,2), we can find the equation by plugging in this info into the point-slope formula

Point-Slope Formula:

where m is the slope and (,) is the given point

Plug in , , and

Distribute

Multiply

Add to both sides to isolate y

Make into equivalent fractions with equal denominators

Combine the fractions

Reduce any fractions

So the equation of the line that is parallel to and goes through (,) is

So here are the graphs of the equations and

graph of the given equation (red) and graph of the line (green) that is parallel to the given graph and goes through (,)

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