SOLUTION: Can you please help me solve this. I know the answer is yes but cannot seem to work out the steps. Virginia's AT&T 9002 cordless phone has a range of 1000 ft. Her apartment is a

Algebra ->  Algebra  -> Length-and-distance -> SOLUTION: Can you please help me solve this. I know the answer is yes but cannot seem to work out the steps. Virginia's AT&T 9002 cordless phone has a range of 1000 ft. Her apartment is a       Log On

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 Question 243354: Can you please help me solve this. I know the answer is yes but cannot seem to work out the steps. Virginia's AT&T 9002 cordless phone has a range of 1000 ft. Her apartment is a corner unit, located as shown in the figure below. Will Virginia be able to use the phone at the community pool? picture shows the distance from the apartment to the ground is 180 ft., the distance from the ground on the outside of the building to the far side of the grounds is 600 ft., and the distance from the far side of the grounds to the far side of the pool is 400 ft. (looks like a U shape)Answer by oberobic(2304)   (Show Source): You can put this solution on YOUR website!Visualize a triangle where the hypotenuse is from Virginia's apartment down to either the far side of the grounds or the pool. The distance across the ground is either 400 or 600. The distance vertically up the side of the building is 180. So apply the Pythagorean formula: c^2 = a^2 + b^2. We know a = 180 and b = 400 or 600. . c^2 = (180)^2 + (400)^2 c^2 = 32,400 + 160,000 = 192,400 c = sqrt (192,400) = 438.63 . c^2 = (180)^2 + (600)^2 c^2 = 32,400 + 360,000 = 392,400 c = sqrt(392,400) = 626.41