SOLUTION: Q.1: Find the lenghts of the sides of the triangle with vertices A(-4,0), B(3,4) and C(4,1).show that the triangle ABC is isosceles?

Algebra ->  Algebra  -> Length-and-distance -> SOLUTION: Q.1: Find the lenghts of the sides of the triangle with vertices A(-4,0), B(3,4) and C(4,1).show that the triangle ABC is isosceles?      Log On

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Question 214194: Q.1: Find the lenghts of the sides of the triangle with vertices A(-4,0), B(3,4) and C(4,1).show that the triangle ABC is isosceles?
Answer by Edwin McCravy(6938) About Me  (Show Source):
You can put this solution on YOUR website!
Q.1: Find the lengths of the sides of the triangle with vertices A(-4,0), B(3,4) and C(4,1).show that the triangle ABC is isosceles?

drawing%28400%2C400%2C-5%2C5%2C-5%2C5%2Cgraph%28400%2C400%2C-5%2C5%2C-5%2C5%29%2C%0D%0Alocate%28-5%2C0%2B.5%2C%27A%28-4%2C0%29%27%29%2C+locate%283%2C4.5%2C%27B%283%2C4%29%27%29%2C+locate%284%2C1%2C%27C%284%2C1%29%27%29%2C%0D%0Atriangle%28-4%2C0%2C3%2C4%2C4%2C1%29+%29

There are two ways. It will be instructive to learn
both methods.

Find the length of AB by drawing this blue
right triangle with AB as its hypotenuse: 

drawing%28400%2C400%2C-5%2C5%2C-5%2C5%2Cgraph%28400%2C400%2C-5%2C5%2C-5%2C5%29%2C%0D%0Alocate%28-5%2C0%2B.5%2C%27A%28-4%2C0%29%27%29%2C+locate%283%2C4.5%2C%27B%283%2C4%29%27%29%2C+locate%284%2C1%2C%27C%284%2C1%29%27%29%2C%0D%0Atriangle%28-4%2C0%2C3%2C4%2C4%2C1%29%2C+blue%28line%28-4%2C0%2C3%2C0%29%29%2C+blue%28line%283%2C0%2C3%2C4%29%29%2C%0D%0Ablue%28line%283%2C4%2C-4%2C0%29%29%0D%0A+%29

The bottom leg of the blue triangle is obviously 7 units long.
(The bottom leg looks purple since it's blue over a red x-axis).
You can just count them. And the right leg of the blue triangle 
is obviously 4 units tall.  You can tell by looking at the units 
of the y axis.

Now AB is the hypotenuse of the blue right triangle. So we use
the Pythagorean theorem:

AB%5E2=7%5E2%2B4%5E2
AB%5E2=49%2B16
AB%5E2=65
AB=sqrt%2865%29

Now we erase the blue right triangle and draw a
green one:

We find the length of AC by drawing this green
right triangle with AC as its hypotenuse:

drawing%28400%2C400%2C-5%2C5%2C-5%2C5%2Cgraph%28400%2C400%2C-5%2C5%2C-5%2C5%29%2C%0D%0Alocate%28-5%2C0%2B.5%2C%27A%28-4%2C0%29%27%29%2C+locate%283%2C4.5%2C%27B%283%2C4%29%27%29%2C+locate%284%2C1%2C%27C%284%2C1%29%27%29%2C%0D%0Atriangle%28-4%2C0%2C3%2C4%2C4%2C1%29%2C+green%28line%28-4%2C0%2C4%2C0%29%29%2C+green%28line%284%2C0%2C4%2C1%29%29%2C%0D%0Agreen%28line%284%2C1%2C-4%2C0%29%29%0D%0A+%29 

The bottom leg of the green triangle is obviously 8 units long.
And the right leg of the green triangle is obviously 1 unit tall.

Now AC is the hypotenuse of the green right triangle. So we use
the Pythagorean theorem:

AC%5E2=8%5E2%2B1%5E2
AC%5E2=64%2B1
AC%5E2=65
AC=sqrt%2865%29

So the lengths of AB and AC are both equal tosqrt%2865%29.
Therefore triangle ABC is isosceles.

HERE'S THE SECOND WAY;

Use the distance formula to find AB:

d=sqrt%28%28x%5B2%5D-x%5B1%5D%29%5E2%2B%28y%5B2%5D-y%5B1%5D%29%5E2%29
AB=sqrt%28%283-%28-4%29%29%5E2%2B%284-0%29%5E2%29
AB=sqrt%28%283%2B4%29%29%5E2%2B%284%29%5E2%29
AB=sqrt%287%5E2%2B4%5E2%29
AB=sqrt%2849%2B16%29
AB=sqrt%2865%29

Use the distance formula to find AC:

d=sqrt%28%28x%5B2%5D-x%5B1%5D%29%5E2%2B%28y%5B2%5D-y%5B1%5D%29%5E2%29
AC=sqrt%28%284-%28-4%29%29%5E2%2B%281-0%29%5E2%29
AC=sqrt%28%284%2B4%29%5E2%2B%281%29%5E2%29
AC=sqrt%288%5E2%2B1%5E2%29
AC=sqrt%2864%2B1%29
AC=sqrt%2865%29

So the lengths of AB and AC are both equal tosqrt%2865%29.
Therefore triangle ABC is isosceles.

Edwin