SOLUTION: Hey, thankyou for the help..The question is_ a open carboard measures a base of 3m x 1m and has a height of 3m. a spider in corner A moves across the surface of box to point B.

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The shortest distance between two points is a straight line and in this case, it's the diagonal that runs from corner to corner. I'm assuming that the spider is traveling from an upper corner to a bottom corner (or vice versa).


It turns out that the diagonal 'd' can be found by the formula


where 'a', 'b', and 'c' are the lengths of the box.


Note: this is analogous to the Pythagorean Theorem.



So in this case, a=3, b=1, and c=3 giving us the equation





Square each value


Combine like terms.


Take the square root of both sides. Note: we're only considering the positive square root.


Approximate the square root.


So the shortest distance that the spider can travel from A to B is roughly 4.359 meters.