SOLUTION: Hey, thankyou for the help..The question is_
a open carboard measures a base of 3m x 1m and has a height of 3m. a spider in
corner A moves across the surface of box to point B.
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Question 207268: Hey, thankyou for the help..The question is_
a open carboard measures a base of 3m x 1m and has a height of 3m. a spider in
corner A moves across the surface of box to point B. Wnat is teh SHORTEST distance that the spider cab travell between A and B. Imagine 3-D cube i.e. like normall room. Sorry for the ammuture drawing was limited.
_____________*A
/ /
/ /
/____________/
3m /
/ 1m
_____________/
*B 3m
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
The shortest distance between two points is a straight line and in this case, it's the diagonal that runs from corner to corner. I'm assuming that the spider is traveling from an upper corner to a bottom corner (or vice versa).
It turns out that the diagonal 'd' can be found by the formula
where 'a', 'b', and 'c' are the lengths of the box.
Note: this is analogous to the Pythagorean Theorem.
So in this case, a=3, b=1, and c=3 giving us the equation
Square each value
Combine like terms.
Take the square root of both sides. Note: we're only considering the positive square root.
Approximate the square root.
So the shortest distance that the spider can travel from A to B is roughly 4.359 meters.
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