SOLUTION: Find the center of the ceircle with equation (x-3)+(y+4)=25.

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Question 200919This question is from textbook Geometry
: Find the center of the ceircle with equation (x-3)+(y+4)=25.























This question is from textbook Geometry

Answer by Alan3354(30993) About Me  (Show Source):
You can put this solution on YOUR website!
Find the center of the ceircle with equation (x-3)+(y+4)=25.
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That's a straight line.
If you meant: (x-3)^2 + (y+4)^2 = 25
then it's a circle with the center at (3,-4).