# SOLUTION: Can somebody help me please? The problem states that a company had sales of \$500,000 in 1996 and sales of \$720,000 in 1998. Use the midpoint formula to find the company's sales in

Algebra ->  Algebra  -> Length-and-distance -> SOLUTION: Can somebody help me please? The problem states that a company had sales of \$500,000 in 1996 and sales of \$720,000 in 1998. Use the midpoint formula to find the company's sales in       Log On

 Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations! Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

 Geometry: Length, distance, coordinates, metric length Solvers Lessons Answers archive Quiz In Depth

 Question 198306: Can somebody help me please? The problem states that a company had sales of \$500,000 in 1996 and sales of \$720,000 in 1998. Use the midpoint formula to find the company's sales in 1997. I will appreciate if you can help me.Found 2 solutions by jim_thompson5910, MCAT:Answer by jim_thompson5910(28595)   (Show Source): You can put this solution on YOUR website!Simply average the years to get: . So the midpoint in between 1996 and 1998 is 1997 (which is expected) Since we averaged the years, we need to average the sales figures: So the company's sales in 1997 was \$610,000. Answer by MCAT(6)   (Show Source): You can put this solution on YOUR website! The question is asking you to basically find the mean of the data: Mean=(Data 1+ Data 2)/(divided)Number of data Our data here are \$500,000 and \$720,000, so here is the equation: Company's sales in 1997(mean)=(\$500,000+\$720,000)/2 =\$1,220,000/2 =\$610,000 Therefore, the company's sales in 1997 were worth \$610,000 (estimation)