# SOLUTION: Perimeter of a rectangle is 32 inches, area of the rectangle is 60 square inches. What is the length and width?

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 Question 193054: Perimeter of a rectangle is 32 inches, area of the rectangle is 60 square inches. What is the length and width?Answer by jonvaliente(64)   (Show Source): You can put this solution on YOUR website!Perimeter=2*L + 2*W Area = L*W Let L=length and W=width of your rectangle If Perimeter=32, then 2*L+2*W=32 (1) If Area=60, then L*W=60 (2) Let's take (1), and express L in terms of W: 2L + 2W = 32 L + W = 16 (divide bot sides by 2) L = 16-W (subtract W from both sides) We can now substitute this value of L in (2), so: (Simplifying) (Add W^2-16W on both sides) (Factoring) If we take W-6=0, W=6 and L=16-W=16-6=10 inches, so our rectangle is 6 inches wide and 10 inches long If we take W-10=0 W=10 and L=16-10=6 inches, but generally length is longer than width so we just take the first solution.