SOLUTION: Using the segment addition postulate to solve for the variable. Suppose M is between L and N. Find the lengths of LM, MN, and LN. LM = 7y + 9 MN = 3y + 4 LN = 143 We saw him wr

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Question 152614This question is from textbook Geometry
: Using the segment addition postulate to solve for the variable. Suppose M is between L and N. Find the lengths of LM, MN, and LN.
LM = 7y + 9
MN = 3y + 4
LN = 143
We saw him write up an example and notes but I have no clue what to do. Thank you
This question is from textbook Geometry

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
It's always helpful to draw a picture


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Since LN is the entire segment and LM and MN are segments that make up LN, this means that LM+MN=LN (ie the length of LM plus the length of MN equals the length of LN)


So algebraically, this tells us that




Remove the parenthesis.


Combine like terms on the left side.


Subtract from both sides.


Combine like terms on the right side.


Divide both sides by to isolate .


Reduce.



So the length of LM is

LM = 7(13)+9=91+9=100


and the length of MN is

MN = 3(13) + 4 = 39 + 4 = 43


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Answer:

So LM is 100 units long and MN is 43 units long

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