SOLUTION: Find the midpoint of the segment with endpoints (sqrt.96, sqrt.3) and (sqrt.6, sqrt.12).

Algebra.Com
Question 135589: Find the midpoint of the segment with endpoints (sqrt.96, sqrt.3) and (sqrt.6, sqrt.12).
Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!
The x-coordinate of the midpoint of the segment joining (,) and (,) is given by , and the y-coordinate is given by . Just plug in the numbers and do the arithmetic.
RELATED QUESTIONS

Segment s1 has endpoints at (3+{{{sqrt(2)}}},5)$ and $(4,7)$. Segment s2 has endpoints at (answered by KMST)
find the area of a box with dimensions sqrt 3 + sqrt 5 (length) and sqrt 3 + sqrt 5... (answered by stanbon)
find an equation of the line that bisects the obtuse angles formed by the lines with... (answered by solver91311)
76. Simplify. Sqrt(6) Sqrt(14) * Sqrt(7)Sqrt(3) 114. Area of a... (answered by edjones)
This is an expression involving square roots using the FOIL method. (sqrt... (answered by Fombitz)
sqrt(54)-... (answered by jim_thompson5910,stanbon)
simplify {{{ sqrt( 24 )- sqrt( 96 )+ sqrt( 6... (answered by tjansen)
I need to find the answer to the sqrt of -8 ( sqrt -3 - sqrt 5) ugh. I got i sqrt 8 (i... (answered by addingup,MathTherapy)
If {{{a = (sqrt(3)-sqrt(2))/(sqrt(3)+sqrt(2))}}} and {{{b =... (answered by Edwin McCravy)