SOLUTION: Help please I can not figure this out! Thanks so much. The perimeter of a rectangle 48m. The length is 9m more than twice the width. What is the length please? Thank you for your

Algebra ->  Algebra  -> Length-and-distance -> SOLUTION: Help please I can not figure this out! Thanks so much. The perimeter of a rectangle 48m. The length is 9m more than twice the width. What is the length please? Thank you for your       Log On

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Question 126377: Help please I can not figure this out! Thanks so much.
The perimeter of a rectangle 48m. The length is 9m more than twice the width. What is the length please? Thank you for your help.
Found 2 solutions by solver91311, checkley71:
Answer by solver91311(12126) About Me  (Show Source):
You can put this solution on YOUR website!
Let the length be x, because that is the answer we want. The length is 9 more than twice the width, so the width is expressed by %28x-9%29%2F2.

The perimeter of a rectangle is P=2L%2B2W.

2x%2B2%28%28x-9%29%2F2%29=48 because we are given that the perimeter is 48.

2x%2Bx-9=48

3x=57

x=19. The length is 19 meters.

Check the answer. If the length is 19 meters, then the width has to be %2819-9%29%2F2=5. 2%2A19%2B2%2A5=38%2B10=48. Answer checks.

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
L=2W+9
2L+2W=48
2(2W+9)+2W=48
4W+18+2W=48
6W=48-18
6W=30
W=30/6
W=5 ANSWER FOR THE WIDTH.
L=2*5+9
L=10+9
L=19
PROOF:
2*19+2*5=38+10=48