SOLUTION: The abcissa of a point is -4 and its distance from (2,4) is square root of 72. Find the ordinate
Algebra.Com
Question 1203017: The abcissa of a point is -4 and its distance from (2,4) is square root of 72. Find the ordinate
Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
Meaning is some point (-4,y) is distance from the point (2,4).
You know what to do now? (hint: Distance Formula)
Answer by greenestamps(13203) (Show Source): You can put this solution on YOUR website!
abscissa (not abcissa) = x coordinate; ordinate = y coordinate
The two points are (2,4) and (-4,y). By the distance formula...
or
or
ANSWERS: -2 or 10
RELATED QUESTIONS
the vertices of the base of an isosceles triangle are (1,2) & (4,-1). find the ordinate... (answered by Alan3354)
find the point whose distance from (7,-3) is square root of 58 and whose abscissa equals... (answered by richwmiller)
find the point whose distance from (7,-3) is square root of 58 and whose abscissa equals (answered by solve_for_x)
the abscissa of a point p is -6 and its distance from the point q(1,3) is √74. find (answered by stanbon)
Find a point having ordinate 5 which is at a distance of 5 units
from the point (2,... (answered by ewatrrr)
A point whose abscissa and ordinate are equal is square root of 10 units from (-1, -3).... (answered by Alan3354)
The ordinate of a point which is √29 units from (5,1) is twice its abscissa. Find... (answered by sachi)
The abscissa of a point is -6 and its distance from the point (1,3)is square root 74.... (answered by stanbon)
The sum of the distance from a point P to (8,0) and (-8,0) is 20. If the abscissa of P is (answered by josgarithmetic)