SOLUTION: the motion of a particle from 0 is describe by the equation 6S = 2t³ - 15t² + 12t, where S is the distance in mitre and t in time in second. fine the acceleration of the particle

Question 1200801: the motion of a particle from 0 is describe by the equation 6S = 2t³ - 15t² + 12t, where S is the distance in mitre and t in time in second. fine the acceleration of the particle when it is momentarily at rest
Answer by htmentor(1343) (Show Source): You can put this solution on YOUR website!
S(t) = 1/6*(2t³ - 15t² + 12t)
The velocity of the particle is given by dS/dt:
v(t) = t² - 5t + 2
And the acceleration is given by dv/dt:
a(t) = 2t - 5
The particle is at rest when v(t) = 0
0 = t² - 5t + 2 which has solutions t = 0.438447 and 4.561550 s.
So the acceleration is a(0.438447) = -4.123 and a(4.56155) = 4.123 m/s^2
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