SOLUTION: Hi its me again, I already ask this question last time but I still don't get it can you show me how to solve it instead with your solution. ASAP. Thankyou, here is the question. T

Question 1197883: Hi its me again, I already ask this question last time but I still don't get it can you show me how to solve it instead with your solution. ASAP. Thankyou, here is the question.
Three vertices of a parallelogram are ( 5, 12 ), ( 2,7 ) and ( 6, 1 ) joined in the order named. Find the 4th vertex
Found 2 solutions by josgarithmetic, math_tutor2020:
Answer by josgarithmetic(39615) (Show Source): You can put this solution on YOUR website!
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Look at the previously posted solution again.

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Understand the point to be found will be part of two pair of parallel lines.

This point can literally be found graphically at a very low level.
Do you see the needed point will be to the right of the given three points?
Can you find the slope and count the units of (5,12) and (2,7)?
,
.
Answer by math_tutor2020(3816) (Show Source): You can put this solution on YOUR website!

I previously answered on this page here
https://www.algebra.com/algebra/homework/Length-and-distance/Length-and-distance.faq.question.1197663.html

I'll provide a visual for what I'm referring to.

A = (5, 12)
B = (2, 7)
C = (6, 1)
D = (9, 6)
The movement from B to A is "up 5, right 3"
The movement from C to D is also "up 5, right 3"
Both lines have a slope of 5/3, which tells us segment AB is parallel to segment CD.
Use the slope formula to confirm that slopeBC = slopeAD, which will show BC is parallel to AD.

Please let me know if you have further questions.

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