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a 13 foot ladder leans against a wall. The foot of a ladder begins to slide away from the wall
at the rate of 1 foot per minute. When the foot is 5ft from the wall, at what rate is the top
of the ladder is falling?
a.5/12 ft/min.
b.4/3 ft/min.
c.3/4 ft/min.
d.12/5 ft/min.
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Let x be horizontal distance from the wall and y be vertical coordinate.
Then from Pythagoras
x^2 + y^2 = 13^2. (1)
Here x = x(t) and y = y(t) are functions of time, t.
Differentiate equation (1) over t. You will get
2x*x'(t) + 2y*y'(t) = 0,
hence
y't = - (x*x'(t))/y.
Evaluate it at the given values x = 5 ft, x'(t) = 1 ft/minute, y = = = = 12.
You will get y'(t) = - = - 5/12 ft/minute.
ANSWER. The top of the ladder moves vertically down at the rate of 5/12 ft per minute.
Solved.