SOLUTION: A 905 kg test car travels around a 3.25 km circular track. If the magnitude of the centripetal force is 2140 N, what is the car’s speed?
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Question 1187976: A 905 kg test car travels around a 3.25 km circular track. If the magnitude of the centripetal force is 2140 N, what is the car’s speed?
Answer by Bala290(1) (Show Source): You can put this solution on YOUR website!
Cicumference=3.25*1000=3250m
F= 2140N, and M=905km
first, we find radius
circumference=2πr
3250=2πr
r=3250/2π
r=517.25m
Fc=
2140=
=
=1106915
=
=1223.11
v=
v=34.97
v≈35m/s
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