Let the center be K. Draw radii KV and KL [which are 25 in. each. We'll get
that in part d)]. Let's answer part b) first
b)Angle measure of Minor Arc VL
Since inscribed angle VEL is 55°, then 55° is one-half the measure of
its intercepted arc. So minor arc VL is twice 55°, or 110°.
Let's do part a) next
a)Length of Major Arc VL
The measure of major arc VL = 360°-the measure of minor arc VL
= 360-°110°=250°
Let's do part c) next
c)Angle VOL
Since inscribed angle VOL subtends major acc VL, which is 250°, then 250° is
one-half the measure of its intercepted arc. So angle VOL is 125°
d)Length of Chord VL
Since we found minor arc VL to have measure 110° in part a), Central angle
VKL also has measure 110°.
Now we will draw KP perpendicular to VL.
d)Length of Chord VL
Since triangle VKL is isosceles, KP bisects angle VKL, which is 110°, and
angle VKP is 55°.
Since chord VL is twice VP, chord VL has length 40.95760221,
Edwin