In a coordinate plane, the points on the x-axis are the points (x,0) for arbitrary "x". So, the points you are looking for, satisfy this distance equation= 6, or = 36. Square both sides to get (x-2)^2 + 9 = 6^2 (x-2)^2 = 36 - 9 (x-2)^2 = 27 x - 2 = = +/- Hence, there are two values for x = and = . So, the points are A = ( ,0) and B = ( ,0). ANSWER