SOLUTION: The length of each of a square is 1 cm more than the width of a rectangle. the length of hte rectangle is 1 cm less than twice its width. the perimeters of the two figures are equa

Question 1162643: The length of each of a square is 1 cm more than the width of a rectangle. the length of hte rectangle is 1 cm less than twice its width. the perimeters of the two figures are equal. find the dimensions of the rectangle.
Answer by josgarithmetic(39630) (Show Source): You can put this solution on YOUR website!
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The length of each of a square is 1 cm more than the width of a rectangle. the length of hte rectangle is 1 cm less than twice its width. the perimeters of the two figures are equal. find the dimensions of the rectangle.
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w, the width of the rectangle
2w-1, the length of the rectangle
w+1, each side length of the square

The perimeters given as equal.

Simplify and solve,...
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