SOLUTION: Two frequencies of sound are played on an instrument governed by the function n(t)=8cos(20pie*t)cos(1000pie*t). What is the peroid and frequency of the fast and slow oscillation?

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Question 1161865: Two frequencies of sound are played on an instrument governed by the function n(t)=8cos(20pie*t)cos(1000pie*t). What is the peroid and frequency of the fast and slow oscillation? What is ampmitude?
Found 2 solutions by ikleyn, Alan3354:
Answer by ikleyn(52778)   (Show Source): You can put this solution on YOUR website!
.

cos(a)*cos(b) =  + .


There are two harmonic modes in this instrument.


The low frequency is  Hertz = 490 Hertz;  the period is   of a second.


The high frequency is  Hertz = 510 Hertz;  the period is   of a second.


The amplitude is 4 units for each harmonic mode.



Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
No math problems with pie.
Use the Greek letter pi.
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