SOLUTION: A ball is thrown with an initial upward velocity of 5 m/s. What is its velocity after 1.5 seconds, and what is the direction of velocity?

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Question 1160718: A ball is thrown with an initial upward velocity of 5 m/s. What is its velocity after 1.5 seconds, and what is the direction of velocity?
Found 2 solutions by ikleyn, solver91311:
Answer by ikleyn(52776)   (Show Source): You can put this solution on YOUR website!
.

Time to move up, up to the maximum height, is   seconds =  = 0.5 seconds, approximately.


So, after 0.5 s + 0.5 s = 1 second, the ball will return to the original height/level, moving down,


and what will happen after that, depends on the level of the starting point.


Since the problem is silent about it, it is a provocative problem.


Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!


Depends on where the ball was launched. If the ball started at ground level, then the velocity is zero with no direction because it hit the ground at roughly 1.0204 seconds. On the other hand, if it was launched from the edge of a structure that was in excess of -3.525 meters tall such that the ball when it was falling missed the roof and continued to the ground, then the velocity was downward and the magnitude found by taking the first derivative of the height function relative to the point of launch, , evaluated at


John

My calculator said it, I believe it, that settles it
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