SOLUTION: In an art gallery, the curator organized the exhibition. 10 same sized pictures were displayed on the wall. The curator gave 0.5m gap between each picture and put 1.5m distance at

Question 1155789: In an art gallery, the curator organized the exhibition. 10 same sized pictures were displayed on the wall. The curator gave 0.5m gap between each picture and put 1.5m distance at both edges of the wall. If each frame is 2.8m long, what is the length (in meters) of the wall?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!

10 pictures of 2.8 m long = 28 m
9 gaps between 10 pictures 0.5 m= 4.5 m
1.5 m the 2 ends = 3 m
Wall length = 28+4.5+3 m
RELATED QUESTIONS
Can someone help me solve this problem? A museum curator can use the equation C = 3x + (answered by rothauserc)

The art gallery had 6 rooms each room had 8 paintings display on it Small how many... (answered by ikleyn)

A new artifact flown from Egypt is to be displayed at the Birmingham Museum and Art... (answered by ikleyn)

An art gallery has a total of 11 art paintings by a particular artist; of these, 5 are... (answered by greenestamps)

There are 6 artists each presenting 5 works of art in an art contest. The 4 works judged (answered by edjones)

There are 6 artists each presenting 5 works of art in an art contest. The 4 works judged... (answered by sudhanshu_kmr)

3 in every 5 of the 400 visitors who came to the art exhibition were adults. How many... (answered by jorel1380)

An art gallery has a total of 11 paintings by a particular artist; of these, 5 are oil... (answered by stanbon)

Advanced-purchased tickets to an art exhibition cost $10, while tickets purchased at the... (answered by ewatrrr)