SOLUTION: Find the point (1,b) is the equidistant from (-2,3) and (2,5) . What are the possible values of b?

Question 1149154: Find the point (1,b) is the equidistant from (-2,3) and (2,5) . What are the possible values of b?
Answer by ikleyn(52908) (Show Source): You can put this solution on YOUR website!
.


The distance formula


     +  =  + 


     + 9       =  + 1

           = 

    -6b + 18         = 26 - 10b

     10b - 6b        = 26 - 18

     4b              = 8

      b              = 8/4 = 2.     ANSWER

Solved.

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