SOLUTION: Could someone please help me I've tried like 5 times and keep getting the wrong answer. Suppose you drop a ball from a window 15 meters above the ground. The ball bounces to 60% o

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Question 1141419: Could someone please help me I've tried like 5 times and keep getting the wrong answer.
Suppose you drop a ball from a window 15 meters above the ground. The ball bounces to 60% of its previous height with each bounce. What is the total number of meters (rounded to the nearest tenth) the ball travels between the time it is dropped and the 10th bounce?
A 37.3 meters
B 378.6 meters
C 59.5 meters
D 63.4 meters

Found 3 solutions by Theo, greenestamps, Edwin McCravy:
Answer by Theo(13342)   (Show Source): You can put this solution on YOUR website!
i believe your answer will be 37.3 meters.

this is a geometric series type question.

the formula is Sn = a * (1 - r ^ n) / (1 - r)

a is the starting number which is 15.

with 10 bounces, the formula becomes S10 = 15 * (1 - .6 ^ 10) / (1 - .6)

solve for S10 to get S10 = 37.27325184.

that rounded to 37.3.

i believe that's going to be your selection.


Answer by greenestamps(13200)   (Show Source): You can put this solution on YOUR website!


The solution by the other tutor is not correct. In his solution, the distances the ball travels are

15, 9, 5.4, ...

But when the ball is dropped from 15 meters and bounces up to 9 meters, it then falls back 9 meters. So the distances the ball travels are

15, 9, 9, 5.4, 5.4, ...

Starting from his answer of 37.3, you can get the right answer by doubling his answer (to get the whole series of numbers twice) and then subtracting 15 (because the 15 occurs only once): 37.3*2-15 = 59.6.

So answer C.

The formula for the sum of a finite geometric series is far more difficult to use than the formula for the sum of an infinite geometric series. In this problem, the sum of the series after 10 bounces is very close to the infinite sum, so I would work the problem using the formula for an infinite sum, knowing that the sum after 10 bounces is just a bit less than the infinite sum.

Probably the easiest way to solve the problem, then, is this:

(1) double the first 15 to make the series 15, 15, 9, 9, 5.4, 5.4, ...;
(2) use the formula for the infinite sum on the series 15, 9, 5.4, ...;
(3) double that answer; and
(4) subtract the "extra" 15

The formula for the infinite sum is



where a is the first term and r is the common ratio.





The infinite sum for the problem is 60 meters, so the sum after 10 bounces has to be the answer choice that is slightly less than 60: answer C.

Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!
You may have made your mistake because you didn't take into account that the
ball drops one more time than it rises.  The second solution above is correct,
but you may not have studied the infinite geometric series, since your problem
stops at the 10th bounce.

If D represents a downward drop of the ball and U represents a upward bounce
of the ball, then the ball's path goes DUDUDUDUDUDUDUDUDUD.  Break it up as: 

D UD UD UD UD UD UD UD UD UD

The initial D is 15 meters. So let's keep that separate and add it in after
we've calculated the other distances the ball travels, which is

   UD UD UD UD UD UD UD UD UD

After the first "D", the ball does only 9 more "UD"'s.

The very first time the ball goes upward, it goes up 60% of 15 meters or 9
meters.
Then it drops 9 meters so that means the first total "UD" is 9+9=18 meters. 

So the geometric series has first term a1 = 18 meters and common ratio r = 60%
or r = 0.6

The formula for the sum of a geometric series with n=9, a1=18 and r=0.6 is

}




That works out with a calculator to be 44.54650368, then when we
add the initial drop of 15 meters, we get

59.54650368 which rounds to 59.5 meters.

Edwin

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