SOLUTION: Given an ellipse: x^2/36+y^2/32=1. Determine the distance between the foci. Please explain.
Algebra.Com
Question 1115786: Given an ellipse: x^2/36+y^2/32=1. Determine the distance between the foci. Please explain.
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
Given an ellipse:
This is the form of an ellipse. Use this form to determine the values used to find the center along with the major and minor axis of the ellipse.
so, , -> center is at (,)= (,)
->
->
Find , the distance from the center to a focus using following formula:
or
Find the foci:
the first focus of an ellipse can be found by adding to
.
(,)=(,)
the second foci
(,)=(,)=(,)
the distance between the foci:
RELATED QUESTIONS
What are the foci of the ellipse given by the equation [((x-2)^2)/36]+[((y-8)^2)/144]=1?
(answered by graphmatics)
The foci and ellipse :... (answered by lwsshak3)
find the foci of the ellipse with the equation:
x^2\16 +... (answered by ewatrrr)
Find the foci of the ellipse with the equation:... (answered by lwsshak3)
ellipse in standard form:
(1/6)(x+2)^2 + (1/9)(y-5)^2= 1
find the center,
foci,... (answered by Mathtut)
find foci of the ellipse... (answered by Gogonati)
i must figure the x intercepts, y intercepts and the foci of this ellipse? x^2/25... (answered by Theo)
Choose the equation that best represents an ellipse for the given foci and co-vertices.
(answered by Edwin McCravy)