SOLUTION: Two cities are 73.5km apart. Vehicle A leaves one city at the same time vehicle B leaves the other. Find the speed of vehicle A if it travels 6.8 km/h faster than vehicle B and if

Question 1094870: Two cities are 73.5km apart. Vehicle A leaves one city at the same time vehicle B leaves the other. Find the speed of vehicle A if it travels 6.8 km/h faster than vehicle B and if they pass in 17.3 minutes.
Found 2 solutions by KMST, MathTherapy:
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
= speed of B in km/h
= speed of A in km/h

If A and B are traveling towards each other,
they will pass somewhere between the two cities.
That will happen in or .
At that time, the distances covered by each vehicle will be
for B, and for A.
You can calculate an approximate decimal value for that , and use it from now on
The sum of those distances is, of course, 73.5km, so the equation to solve is
.

Solving:

The result of that calculation is
or or .
So is the speed of B in km/h.
The speed of A, in km/h, is

Answer by MathTherapy(10555) (Show Source): You can put this solution on YOUR website!
Two cities are 73.5km apart. Vehicle A leaves one city at the same time vehicle B leaves the other. Find the speed of vehicle A if it travels 6.8 km/h faster than vehicle B and if they pass in 17.3 minutes.

Let A's speed be S
Then B's speed = S - 6.8
Since distances they covered when they "met," sum to 73.5, we get the following DISTANCE equation:
17.3S + 17.3S - 17.3(6.8) = 60(73.5) ------ Multiplying by LCD, 60
34.6S = 60(73.5) + 17.3(6.8)
S, or A's speed =
That's all! I hate working problems that don't have INTEGER solutions.
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