SOLUTION: A man built a walk of uniform width around a rectangular pool. If the area of the walk is 273 square feet and the dimensions of the pool are 19 feet by 13 feet, how wide is the wal

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Question 1093886: A man built a walk of uniform width around a rectangular pool. If the area of the walk is 273 square feet and the dimensions of the pool are 19 feet by 13 feet, how wide is the walk?


Answer by ikleyn(52777)   (Show Source): You can put this solution on YOUR website!
.
Let x be that unknown width, in feet.


The area of the pool is 19*13 sq. ft.


The exterior dimensions of the larger rectangle are (19+2x) ft and (13+2x) ft.


Hence, the area of the larger rectangle is the product  (19+2x)*(13+2x) sq. ft.


Then the area of the walkway around the pool is the difference  (19+2x)*(13+2x) - 19*13.


So, your equation expressing this area is

(19+2x)*(13+2x) - 19*13 = 273.


Solve it and find x.

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To see more samples/examples of solved problems of this type, look into the lesson
    - Problems on the area and the dimensions of a rectangle surrounded by a strip
in this site.


Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lesson is the part of this online textbook under the topic
"Dimensions and the area of rectangles and circles and their elements".



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