SOLUTION: three consecutive vertices of a parallelogram are (1 -3), (-3 -1) (3 5). find the fourth vertex drawing pls.

Question 1045525: three consecutive vertices of a parallelogram are (1 -3), (-3 -1) (3 5). find the fourth vertex
drawing pls.
Found 2 solutions by ewatrrr, robertb:
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

m =
(-3,-1)
( 1, -3) m = 2/-4 = 1/-2 = 3/-6 or P(-3,8) which is back 6 & up 3 from P(3.5)
(1,-3),
(3,5), m = -8/-2 = 4 = 8/2 or P(-1,7) which is up 2 & up 8 from P( -3,-1)
P(-1,7) the fourth vertex
Using graph paper one could also sketch the green lines to fing the fouth vertes P(-1,7)
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
Please note that, if you give any three vertices of a quadrilateral (in particular a parallelogram), then they will always
be "consecutive".
With that said, there would be three possible 4th vertices,
namely (-1, 7), (7,3), and (-5, -9).
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