SOLUTION: find the area of a triangle with the vertices ( 7.-9), (-1,6),(-1,-9)

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Question 1045419: find the area of a triangle with the vertices ( 7.-9), (-1,6),(-1,-9)
Found 3 solutions by josgarithmetic, advanced_Learner, MathTherapy:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
Use the length from (7,-9) to (-1,-9) as a base of the triangle.
Use the length from (-1,6) to (-1,-9) as the height of the triangle.

If b is BASE and h is HEIGHT, then formula for area of a triangle is .
Answer by advanced_Learner(501)   (Show Source): You can put this solution on YOUR website!
let A( 7.-9), B(-1,6),C(-1,-9)
=
=
=
=
=
=
Since=
the hypotenus is 17
=
=
Answer by MathTherapy(10551)   (Show Source): You can put this solution on YOUR website!

find the area of a triangle with the vertices ( 7.-9), (-1,6),(-1,-9)
Let points (7, - 9), (- 1, 6), and (- 1, - 9) be A, B, and C, respectively

We then have: A(7, - 9), B(- 1, 6), C(- 1, - 9)

Line AC is parallel to the x-axis, and so, its length is: 7 - - 1, or 7 + 1, or 8 units

Line BC is parallel to the y-axis, and so, its length is: 6 - - 9, or 6 + 9, or 15 units

We now see that the polygon is a right-triangle, and that AC and BC are its legs. 

Therefore, area = , or  

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