SOLUTION: Amacha leaves her office at 8:00 am and drives to a client's office at an average rate of 80kph.She spends 2 hours in meeting,takes a 1 hour lunch and returns to her own office,

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Question 1043957: Amacha leaves her office at 8:00 am and drives to
a client's office at an average rate of 80kph.She
spends 2 hours in meeting,takes a 1 hour lunch
and returns to her own office,driving at an average
of 60kph.If she arrives back at her office at 3:00 pm,
how far apart are the two offices?

Found 2 solutions by Alan3354, ikleyn:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Amacha leaves her office at 8:00 am and drives to
a client's office at an average rate of 80kph.She
spends 2 hours in meeting,takes a 1 hour lunch
and returns to her own office,driving at an average
of 60kph.If she arrives back at her office at 3:00 pm,
how far apart are the two offices?
--------
She spends 4 hours driving.
---
Avg speed for the round trip = 2*80*60/(80+60) = 480/7 km/hr
RT distance = 4*480/7 km
Each way = 960/7 kms

Answer by ikleyn(52776)   (Show Source): You can put this solution on YOUR website!
.
Amacha leaves her office at 8:00 am and drives to
a client's office at an average rate of 80kph. She
spends 2 hours in meeting,takes a 1 hour lunch
and returns to her own office,driving at an average
of 60kph.If she arrives back at her office at 3:00 pm,
how far apart are the two offices?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Amacha spent driving 7 hours - 3 hours = 4 hours.

Led D be the distance between the offices.

Then you have this equation for the unknown D

 = 4,   (1)

where 4 = 4 hours is the total driving time.

To solve (1), multiply both sides by the Least Common Denominator 240. You will have

3D + 4D = 4*240,   or   7D = 960.

Hence, D =  = 137.14 miles.

Solved.


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