SOLUTION: the coordinate of a point P is twice the abscissa. this point is equidistant from (-3,1) and (8,-2) find the coordinates of P.

Question 1030962: the coordinate of a point P is twice the abscissa. this point is equidistant from (-3,1) and (8,-2) find the coordinates of P.

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
he coordinate of a point P is twice the abscissa. this point is equidistant from (-3,1) and (8,-2) find the coordinates of P.
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P = (k,2k)
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Distance from (-3,1):
sqrt[(k+3)^2+(2k-1)^2]
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Distance from (8,-2)
sqrt[(k-8)^2+(2k+2)^2]
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Equation:
(k+3)^2+(2k-1)^2 = (k-8)^2+(2k+2)^2
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Solve for "k" and "2k"
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Cheers,
Stan H.
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