SOLUTION: Hi, here is my problem that I have. I'm pretty sure it uses the distance/midpoint formula.
There is no picture for this.
A(1,3), B(7,5), C(9,-3) are the vertices of Triangle ABC
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Question 1005548: Hi, here is my problem that I have. I'm pretty sure it uses the distance/midpoint formula.
There is no picture for this.
A(1,3), B(7,5), C(9,-3) are the vertices of Triangle ABC. E is the midpoint of AB, and F is the midpoint of BC. Show that EF is parallel to AC.
Answer by ikleyn(52803) (Show Source): You can put this solution on YOUR website!
.
The straight line connecting midpoints of two sides of a triangle is parallel to the third side of the triangle.
It is well known and famous / general property (theorem) which valid for any triangle in a plane.
See the lesson The line segment joining the midpoints of two sides of a triangle in this site.
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