SOLUTION: Find the point on each median that is two-thirds of the distance from the vertec to the midpoint if the vertices of the triangle are A (4,-4), B (10,4) & C (2,6)

Question 1004861: Find the point on each median that is two-thirds of the distance from the vertec to the midpoint if the vertices of the triangle are A (4,-4), B (10,4) & C (2,6)
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!
The midpoints are
(7,0),(6,5),(3,1)

The midpoint of the triangle is the length of the median.
Find one vertex, and go the way to the midpoint of the opposite side. Directions matter. Start at the point, and take the value and the value.
The easiest one is from (,) to (,)
The -value is from to . The distance is , and of that is , or .
So the -value is or .

The -value is from to , or . The -value is .
The midpoint is (,).
This will work for the other two points to the opposite side midpoint.

or, you can do it this way:
take two vertices and two midpoints and find the equations of the lines passing through one midpoint and opposite vertices
R(7,0) and C (2,6)

Solved by pluggable solver: Find the equation of line going through points

hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (7, 0) and (x2, y2) = (2, 6).
Slope a is .
Intercept is found from equation , or . From that,
intercept b is , or .

y=(-1.2)x + (8.4)

Your graph:

Q(6,5) and A (4,-4)

Solved by pluggable solver: Find the equation of line going through points

hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (6, 5) and (x2, y2) = (4, -4).
Slope a is .
Intercept is found from equation , or . From that,
intercept b is , or .

y=(4.5)x + (-22)

Your graph:

so, your equations are:
and

-----------------find intersection
since left sides equal, make right sides equal and solve for

find

intersection point is at (,) and that is your midpoint

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