SOLUTION: Find the lengths of the sides of the triangle and area with the vertices A(-2,-3) B(6,1) & C (-2,-5)

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Question 1004834: Find the lengths of the sides of the triangle and area with the vertices A(-2,-3) B(6,1) & C (-2,-5)
Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!

Find the lengths of the sides of the triangle and area with the vertices:
A(,) B(,) & C (,)
use distance formula:
the length of is
Solved by pluggable solver: Distance Formula


The first point is (x1,y1). The second point is (x2,y2)


Since the first point is (-2, -3), we can say (x1, y1) = (-2, -3)
So ,


Since the second point is (6, 1), we can also say (x2, y2) = (6, 1)
So ,


Put this all together to get: , , , and

--------------------------------------------------------------------------------------------


Now use the distance formula to find the distance between the two points (-2, -3) and (6, 1)






Plug in , , , and






















==========================================================

Answer:


The distance between the two points (-2, -3) and (6, 1) is exactly units


The approximate distance between the two points is about 8.94427190999916 units



So again,


Exact Distance: units


Approximate Distance: units





the length of is
Solved by pluggable solver: Distance Formula


The first point is (x1,y1). The second point is (x2,y2)


Since the first point is (-2, -3), we can say (x1, y1) = (-2, -3)
So ,


Since the second point is (-2, -5), we can also say (x2, y2) = (-2, -5)
So ,


Put this all together to get: , , , and

--------------------------------------------------------------------------------------------


Now use the distance formula to find the distance between the two points (-2, -3) and (-2, -5)






Plug in , , , and
















==========================================================

Answer:


The distance between the two points (-2, -3) and (-2, -5) is exactly 2 units





the length of is
Solved by pluggable solver: Distance Formula


The first point is (x1,y1). The second point is (x2,y2)


Since the first point is (-2, -5), we can say (x1, y1) = (-2, -5)
So ,


Since the second point is (6, 1), we can also say (x2, y2) = (6, 1)
So ,


Put this all together to get: , , , and

--------------------------------------------------------------------------------------------


Now use the distance formula to find the distance between the two points (-2, -5) and (6, 1)






Plug in , , , and













==========================================================

Answer:


The distance between the two points (-2, -5) and (6, 1) is exactly 10 units





so, ,, and


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