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for this problem, where:
d = distance traveled.
r = rate (speed) of travel.
t = time taken to travel distance d at a speed of r.
For the car, r = 90 km/h.
For the train, r = 75 km/h
![d[c] = 90(t-2)](/cgi-bin/plot-formula.mpl?expression=d%5Bc%5D+=+90%28t-2%29&x=0003)
(t-2 because the car takes 2 hours less than the train).
![d[t] = 75t](/cgi-bin/plot-formula.mpl?expression=d%5Bt%5D+=+75t&x=0003)
The distance is the same for each, so...

Subtract 75t from both sides.

Add 180 to both sides.

Divide both sides by 15.

Now substitute this into either one of the two distance equations.
For the car:
![d[c] = 90(t-2)](/cgi-bin/plot-formula.mpl?expression=d%5Bc%5D+=+90%28t-2%29&x=0003)
Substitute t = 12.
![d[c] = 900](/cgi-bin/plot-formula.mpl?expression=d%5Bc%5D+=+900&x=0003)
km.
For the train:
![d[t] = 75t](/cgi-bin/plot-formula.mpl?expression=d%5Bt%5D+=+75t&x=0003)
Substitute t = 12.
![d[t] = 900](/cgi-bin/plot-formula.mpl?expression=d%5Bt%5D+=+900&x=0003)
km.
The towns are 900 km. apart.