You can
put this solution on YOUR website!distance = rate*time
lets call one cyclist d1=r1(t1)
and the other cyclist d2=r2(t2)
t1=t2=3hours
d2=90-d1
r1=2(r2)---->r1/2
so d1=r1(3)
and 90-d1=r2(3)
substitute value of d1 into 2nd equation and remember r2=r1/2
90-(3(r1))=((r1)/2)(3)---->90-3(r1)=3/2(r1)----->180-6(r1)=3(r1)--->9(r1)=180
r1=20kmph
r2=10kmph