|
Tutors Answer Your Questions about Inverses (FREE)
Question 415948: This is the only inverse-related section, so, here goes:
Find the inverse function of Y = (exp)3(sqrt)2x+1
I get that you turn f(x) into Y, and replace the X with Y, and vice versa; then move the (exp)3 onto the Y to get rid of the square root. So, it then becomes:
X^3 = 2Y+1
After that, I'm lost. If I subtract the 1, it becomes X^3-1 = 2Y, but, I can't divide by 2 because there needs to be an X in the denominator.
Click here to see answer by stanbon(57387)  |
Question 415948: This is the only inverse-related section, so, here goes:
Find the inverse function of Y = (exp)3(sqrt)2x+1
I get that you turn f(x) into Y, and replace the X with Y, and vice versa; then move the (exp)3 onto the Y to get rid of the square root. So, it then becomes:
X^3 = 2Y+1
After that, I'm lost. If I subtract the 1, it becomes X^3-1 = 2Y, but, I can't divide by 2 because there needs to be an X in the denominator.
Click here to see answer by jim_thompson5910(28598) |
Question 420085: In order to earn an A in a class, your test scores must average at least 92%. On the first 6 tests, you have an average of 91%. What score do you need to get on the last test to earn an A? Show your work.
Well I tried it myself And I think it's set out like this: 91+6=>92 I don't know If this is the right way to set it up. =/
Click here to see answer by stanbon(57387) |
Question 420085: In order to earn an A in a class, your test scores must average at least 92%. On the first 6 tests, you have an average of 91%. What score do you need to get on the last test to earn an A? Show your work.
Well I tried it myself And I think it's set out like this: 91+6=>92 I don't know If this is the right way to set it up. =/
Click here to see answer by josmiceli(9697)  |
Question 420085: In order to earn an A in a class, your test scores must average at least 92%. On the first 6 tests, you have an average of 91%. What score do you need to get on the last test to earn an A? Show your work.
Well I tried it myself And I think it's set out like this: 91+6=>92 I don't know If this is the right way to set it up. =/
Click here to see answer by Edwin McCravy(8909)  |
Question 424970: I am not sure if this equation was done right. Here it is
1/3+1/2
-------
5/9-1/3
Do I add the first equation to get that answer, subtract the second equation and take both answers and Divide them? Here is what I have on my sheet:
1/3+1/2 2/6+3/6 5/6
-------= -------= ---=5/6 * 9/2 = 5/6 * 27/6 = 45/12 ?
5/9-1/3 5/9-3/9 2/9
Is this any where close to being right?
Click here to see answer by Alan3354(30993)  |
Question 436545: The number of miles per gallon of gasoline that a vehicle averages varies inversely as the average speed the car travels. A vehicle gets 13 miles per gallon at 52 mph. How many miles per gallon will it get at 54 mph?
A) 0.08 miles per gallon
B) 12.5 miles per gallon
C) 0.07 miles per gallon
D) 13.5 miles per gallon
E) none of the above
Click here to see answer by rwm(914) |
|
Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350
|
| |
