|
Tutors Answer Your Questions about Inverses (FREE)
Question 616249: Find the inverse of the following function. Find domain, range, and asymptotes of each function. f(x)=ln(x+1)+1
I tried to solve this but i got mixed up.
Here is what I had.
y=(x+1)+1
x=(y+1)+1
x-1=(y+1)-1
x-2=y
x-2=f^-1(x)
My teacher noted that I didn't add the ln to the equation upon solving.
Would it be x=ln(y+1)+1
Can someone please help me. Thanks
Also for the Domain, I'm guessing that I solve
x+1=0
x=-1 so the domain is (-1,inf)
I thought that there cannot be a domain for x<0.
So confused
Click here to see answer by jim_thompson5910(28549)  |
Question 616717: I am having trouble with inverse operations in having to make x the subject. I have three questions in my workbook.
First question - make x the subject.
v= qx^2/t+p
I tried doing it but I am not sure if I have my working right. My end answer was that it is
x= sqrt(v-pt/q)
Any help would be appreciated thank you. This is the one that I understood the most. The other two absolutely blow my mind. Thanks :)
Click here to see answer by Alan3354(30993)  |
Question 623825: If f(x)= 2/(x-1), then f^-1(x)= ?
The way I tried solving this problem is by switching the x and y, and solving for y. I ended up with the answer f^-1(x)=(2+x)/x. Can you help me decide if this is the right answer, and let me know where I went wrong if this answer is wrong.
Click here to see answer by edjones(7569)  |
Question 623825: If f(x)= 2/(x-1), then f^-1(x)= ?
The way I tried solving this problem is by switching the x and y, and solving for y. I ended up with the answer f^-1(x)=(2+x)/x. Can you help me decide if this is the right answer, and let me know where I went wrong if this answer is wrong.
Click here to see answer by lwsshak3(6490) |
Question 632466: I am trying to find the inverse equation of F(x)= (2-x)/(5x)
I get x=(2-y)/(5y)
multiply 5y through to get (5yx)=(2-y)
I divide the whole equation by y to get (5x)=(2/y)-(y/y) (y/y equaling 1)
so now my equation is 5x=(2/y)-1then take over the one to get 5x+1=2/y
I am not sure how to get y on its own after that please help thank you
Click here to see answer by Alan3354(30993) |
Question 641323: My question is not about solving homework. Next week is midterms and I have a HORRIBLE grade in pre-algebra. We are having a final test over reciprocals. I need a LOT of help. So basically what you do is you swap the number over. So if the division problem is 1/3 divided by 1/2 you would be solving for: 1/3 x 2/1 right? and the answer would be 2/3. Am I correct? Thank you so much for reading.
Click here to see answer by ankor@dixie-net.com(15647)  |
|
Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350
|
| |
