SOLUTION: y varies directly as x and inversely as the square of z. y= 38 when x=32 and z=4. Find y when x=75 and z=5.
y=___
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Question 753778: y varies directly as x and inversely as the square of z. y= 38 when x=32 and z=4. Find y when x=75 and z=5.
y=___
Answer by Cromlix(4381) (Show Source): You can put this solution on YOUR website!
y varies directly as x and inversely as the
square of z
y = kx/z^2
(k is the constant of proportionality)
Using the given values find out k's value
y = kx/z^2
38 = k *32/ 4^2
38 = 32k/16
38 = 2k
k = 19
Put back in formula
y = 19x/z^2
y = 19*75/5^2
y = 1425/25
y = 57
Hope this helps
:-)
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