SOLUTION: There are three consecutive intergers listed in natural order. The sum of the first and half the third is 13 less than the second. (What is natural order?)
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Algebra.Com
Question 662054: There are three consecutive intergers listed in natural order. The sum of the first and half the third is 13 less than the second. (What is natural order?)
Thanks
Answer by ReadingBoosters(3246) (Show Source): You can put this solution on YOUR website!
x x+1 x+2
x + 1/2(x+2) = x+1 - 13
Combine like terms
x + 1/2x + 1/2(2) = x - 12
1 1/2x + 1 = x - 12
1 1/2x - x = -12 - 1
1/2x = -13
x = -26
Integers are -26, -27 and -28
Proof
(-26)+(1/2)(-28) = -26 + -14 = -40
-27 - 13 = -40
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