SOLUTION: solve by factoring. 1) x2-5x+6=0 2) 2x2-9x-5=0 3) 3x2+5x-2=0

Question 6103: solve by factoring.
1) x2-5x+6=0
2) 2x2-9x-5=0
3) 3x2+5x-2=0
Found 2 solutions by Abbey, guapa:
Answer by Abbey(339) (Show Source): You can put this solution on YOUR website!
1) x2-5x+6=0
(x-6)(x+1)=0
x=6, -1
2) 2x2-9x-5=0
(2x+1)(x-5) =0
x=-1/2, 5
3) 3x2+5x-2=0
(3x-1)(x+2)=0
x-1/3,-2
Answer by guapa(62) (Show Source): You can put this solution on YOUR website!
1)

Find the 2 middle terms which are the sum of -5x and a product of 6.

Now use the factoring by grouping method.

Now factor their common term

Solve for x
(x-2)=0, x=2
(x-3)=0, x=3
2)

Proceed as showed above

Solve for x
x-5=0, x=5
(2x+1)=0, x= -1/2
3)

Solve for x
x+2=0, x=-2
(3x-1)=0, x=1/3
Hope it helps
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