# SOLUTION: Write the equation in standard form of the line that is perpendicular to the line y=-2x+6 and passes through the point (-4,8)

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 Click here to see ALL problems on Inverses Question 546420: Write the equation in standard form of the line that is perpendicular to the line y=-2x+6 and passes through the point (-4,8)Answer by mananth(12270)   (Show Source): You can put this solution on YOUR website!1 y = -2 x + 6 Divide by 1 y = -2 x + 6 Compare this equation with y=mx+b, m= slope & b= y intercept slope m = -2 The slope of a line perpendicular to the above line will be the negative reciprocal 0.5 m1*m2=-1 The slope of the required line will be 1/2 m= 1/2 ,point ( -4 , 8 ) Find b by plugging the values of m & the point in y=mx+b 8 = -2.00 + b b= 10 m= 1/2 The required equation is , y = 1/ 2 x + 10 multiply by 2 2y=x+20 -x+2y=20 m.ananth@hotmail.ca