SOLUTION: what is the equation for the line that contains the point (6,-10) and is perpendicular to the line y=-8+x

Question 460211: what is the equation for the line that contains the point (6,-10) and is perpendicular to the line y=-8+x
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
what is the equation for the line that contains the point (6,-10) and is perpendicular to the line y=-8+x
:
Write in the slope/intercept form y = mx+b
y = x - 8
the slope is +1
then the slope of the perpendicular line = -1
:
Use the point/slope form y - y1 = m(x - x1)
in this equation m=-1, x1=6, y1=-10
y - (-10) = -1(x - 6)
y + 10 = -x + 6
y = -x + 6 - 10
y = -x - 4, is the equation
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