SOLUTION: Solve for x. log2 (7+2x) + log2 (4x-1) = 3 Check the validity of each solution in the original equation.

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Question 437728: Solve for x.
log2 (7+2x) + log2 (4x-1) = 3
Check the validity of each solution in the original equation.

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi


2^3 = (2x+7)(4x-1)
8x^2 +26x -15 = 0
factoring
(4x +15)(2x -1) = 0
(4x +15)= 0
x = -15/4 Extraneous solution: (7+2x) and (4x-1) are < 0
(2x -1) = 0
x = 1/2
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