SOLUTION: This is the only inverse-related section, so, here goes:
Find the inverse function of Y = (exp)3(sqrt)2x+1
I get that you turn f(x) into Y, and replace the X with Y, and vice
Algebra.Com
Question 415948: This is the only inverse-related section, so, here goes:
Find the inverse function of Y = (exp)3(sqrt)2x+1
I get that you turn f(x) into Y, and replace the X with Y, and vice versa; then move the (exp)3 onto the Y to get rid of the square root. So, it then becomes:
X^3 = 2Y+1
After that, I'm lost. If I subtract the 1, it becomes X^3-1 = 2Y, but, I can't divide by 2 because there needs to be an X in the denominator.
Found 2 solutions by stanbon, jim_thompson5910:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
y = cbrt(2x+1)
----
1st: Interchange to get:
x = cbrt(2y+1)
cube both sides:
x^3 = 2y+1
---
2y+1 = x^3
2y = x^3 -1
y = (x^3-1)/2
==================
That is the inverse.
===================
Cheers,
Stan H.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
So the inverse function is =\frac{x^3-1}{2})
If you need more help, email me at jim_thompson5910@hotmail.com
Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you
Jim
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